A pipe of uniform correctional of area a has a right-angled bend, impure water of density δ δ flows through the horizontal portion of the pipe. The distance covered by water per second at the bend to keep the pipe in equilibrium against an applied force F at the bend is

Text Solution
Verified by ExpertsThe correct answer is:
D
Force × Time = Change in momentum

or F × Δ Δ t = Δ Δ mv √ √ 2 or F = 
= 
( Q Δ Δ m = ρ ρ a Δ Δ L)
or F =
= v 2 
v = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A Particle of mass 100 gm moves in a potential well given by U = 8x 2 – 4x + 400 Joule. Find its ac…
As shown in the following figures block of mass 2 kg is in equilibrium in the vertical plane.
At …
Interaction between atoms of a diatomic molecule is described by the relation P.E. (x) = , where P…
A particle of mass m = 1 kg, lying on x-axis, experiences a force given by law F = x (3x – 2) N, wh…
A particle has PE vs x curve as shown in Fig. The unstable equilibrium occurs at
A streamlined and almost symmetrical car of mass M has center of gravity at a distance p from the r…